115030257035 has 4 divisors (see below), whose sum is σ = 138036308448. Its totient is φ = 92024205624.

The previous prime is 115030256993. The next prime is 115030257119. The reversal of 115030257035 is 530752030511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530752030511 = 43 ⋅12343070477.

It is a cyclic number.

It is not a de Polignac number, because 115030257035 - 2²² = 115026062731 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115030256992 and 115030257010.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11503025699 + ... + 11503025708.

It is an arithmetic number, because the mean of its divisors is an integer number (34509077112).

Almost surely, 2^115030257035 is an apocalyptic number.

115030257035 is a deficient number, since it is larger than the sum of its proper divisors (23006051413).

115030257035 is an equidigital number, since it uses as much as digits as its factorization.

115030257035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23006051412.

The product of its (nonzero) digits is 15750, while the sum is 32.

Adding to 115030257035 its reverse (530752030511), we get a palindrome (645782287546).

The spelling of 115030257035 in words is "one hundred fifteen billion, thirty million, two hundred fifty-seven thousand, thirty-five".