11503034400145 has 4 divisors (see below), whose sum is σ = 13803641280180. Its totient is φ = 9202427520112.

The previous prime is 11503034400119. The next prime is 11503034400223. The reversal of 11503034400145 is 54100443030511.

11503034400145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7767998874769 + 3735035525376 = 2787113^2 + 1932624^2 .

It is a cyclic number.

It is not a de Polignac number, because 11503034400145 - 2⁵ = 11503034400113 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1150303440010 + ... + 1150303440019.

It is an arithmetic number, because the mean of its divisors is an integer number (3450910320045).

Almost surely, 2^{11503034400145} is an apocalyptic number.

It is an amenable number.

11503034400145 is a deficient number, since it is larger than the sum of its proper divisors (2300606880035).

11503034400145 is an equidigital number, since it uses as much as digits as its factorization.

11503034400145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2300606880034.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 11503034400145 its reverse (54100443030511), we get a palindrome (65603477430656).

The spelling of 11503034400145 in words is "eleven trillion, five hundred three billion, thirty-four million, four hundred thousand, one hundred forty-five".