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11503034400113 is a prime number
BaseRepresentation
bin1010011101100100001001…
…0001110111110101110001
31111201200100020121212222022
42213121002101313311301
53001431203301300423
640244230540321225
72265031626061364
oct247310221676561
944650306555868
1011503034400113
1137354560430a3
121359446b43215
1365596810c049
142baa6d7980db
1514e3488c8dc8
hexa7642477d71

11503034400113 has 2 divisors, whose sum is σ = 11503034400114. Its totient is φ = 11503034400112.

The previous prime is 11503034400041. The next prime is 11503034400119. The reversal of 11503034400113 is 31100443030511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8497499012209 + 3005535387904 = 2915047^2 + 1733648^2 .

It is a cyclic number.

It is not a de Polignac number, because 11503034400113 - 230 = 11501960658289 is a prime.

It is not a weakly prime, because it can be changed into another prime (11503034400119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5751517200056 + 5751517200057.

It is an arithmetic number, because the mean of its divisors is an integer number (5751517200057).

Almost surely, 211503034400113 is an apocalyptic number.

It is an amenable number.

11503034400113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11503034400113 is an equidigital number, since it uses as much as digits as its factorization.

11503034400113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 11503034400113 its reverse (31100443030511), we get a palindrome (42603477430624).

The spelling of 11503034400113 in words is "eleven trillion, five hundred three billion, thirty-four million, four hundred thousand, one hundred thirteen".