11503052444533 has 4 divisors (see below), whose sum is σ = 12387902632588. Its totient is φ = 10618202256480.

The previous prime is 11503052444519. The next prime is 11503052444551. The reversal of 11503052444533 is 33544425030511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2820323901924 + 8682728542609 = 1679382^2 + 2946647^2 .

It is not a de Polignac number, because 11503052444533 - 2²¹ = 11503050347381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11503052444503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 442425094008 + ... + 442425094033.

It is an arithmetic number, because the mean of its divisors is an integer number (3096975658147).

Almost surely, 2^{11503052444533} is an apocalyptic number.

11503052444533 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11503052444533 is a deficient number, since it is larger than the sum of its proper divisors (884850188055).

11503052444533 is an equidigital number, since it uses as much as digits as its factorization.

11503052444533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 884850188054.

The product of its (nonzero) digits is 432000, while the sum is 40.

The spelling of 11503052444533 in words is "eleven trillion, five hundred three billion, fifty-two million, four hundred forty-four thousand, five hundred thirty-three".