Base | Representation |
---|---|
bin | 10101011011010010… |
… | …11011001001001101 |
3 | 1002200200101202021001 |
4 | 22231221123021031 |
5 | 142024313031140 |
6 | 5141242340301 |
7 | 555030012655 |
oct | 125551331115 |
9 | 32620352231 |
10 | 11503252045 |
11 | 497331657a |
12 | 22904ba691 |
13 | 111427aa1c |
14 | 7b1a71365 |
15 | 474d4ae9a |
hex | 2ada5b24d |
11503252045 has 8 divisors (see below), whose sum is σ = 14615896824. Its totient is φ = 8661272064.
The previous prime is 11503252009. The next prime is 11503252067. The reversal of 11503252045 is 54025230511.
It can be written as a sum of positive squares in 4 ways, for example, as 2989683684 + 8513568361 = 54678^2 + 92269^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11503252045 - 223 = 11494863437 is a prime.
It is a super-2 number, since 2×115032520452 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67666104 + ... + 67666273.
It is an arithmetic number, because the mean of its divisors is an integer number (1826987103).
Almost surely, 211503252045 is an apocalyptic number.
It is an amenable number.
11503252045 is a deficient number, since it is larger than the sum of its proper divisors (3112644779).
11503252045 is a wasteful number, since it uses less digits than its factorization.
11503252045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135332399.
The product of its (nonzero) digits is 6000, while the sum is 28.
Adding to 11503252045 its reverse (54025230511), we get a palindrome (65528482556).
The spelling of 11503252045 in words is "eleven billion, five hundred three million, two hundred fifty-two thousand, forty-five".
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