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11503252055 = 52300650411
BaseRepresentation
bin10101011011010010…
…11011001001010111
31002200200101202021102
422231221123021113
5142024313031210
65141242340315
7555030013001
oct125551331127
932620352242
1011503252055
114973316589
1222904ba69b
13111427aa29
147b1a71371
15474d4aea5
hex2ada5b257

11503252055 has 4 divisors (see below), whose sum is σ = 13803902472. Its totient is φ = 9202601640.

The previous prime is 11503252009. The next prime is 11503252067. The reversal of 11503252055 is 55025230511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55025230511 = 487112988153.

It is not a de Polignac number, because 11503252055 - 210 = 11503251031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1150325201 + ... + 1150325210.

It is an arithmetic number, because the mean of its divisors is an integer number (3450975618).

Almost surely, 211503252055 is an apocalyptic number.

11503252055 is a deficient number, since it is larger than the sum of its proper divisors (2300650417).

11503252055 is an equidigital number, since it uses as much as digits as its factorization.

11503252055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2300650416.

The product of its (nonzero) digits is 7500, while the sum is 29.

Adding to 11503252055 its reverse (55025230511), we get a palindrome (66528482566).

The spelling of 11503252055 in words is "eleven billion, five hundred three million, two hundred fifty-two thousand, fifty-five".

Divisors: 1 5 2300650411 11503252055