Base | Representation |
---|---|
bin | 11010001010001101101011… |
… | …111101000101111110101101 |
3 | 120002100202222222120202010111 |
4 | 122022031223331011332231 |
5 | 110034444123113312331 |
6 | 1044405425025340021 |
7 | 33143111341333306 |
oct | 3212155375057655 |
9 | 502322888522114 |
10 | 115051100135341 |
11 | 33727996717767 |
12 | 10aa1810797611 |
13 | 4c273700028a6 |
14 | 205a70818d7ad |
15 | d47b23189db1 |
hex | 68a36bf45fad |
115051100135341 has 16 divisors (see below), whose sum is σ = 115977847265280. Its totient is φ = 114128810241520.
The previous prime is 115051100135333. The next prime is 115051100135351. The reversal of 115051100135341 is 143531001150511.
It is a cyclic number.
It is not a de Polignac number, because 115051100135341 - 23 = 115051100135333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115051100135351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79687050 + ... + 81117988.
It is an arithmetic number, because the mean of its divisors is an integer number (7248615454080).
Almost surely, 2115051100135341 is an apocalyptic number.
It is an amenable number.
115051100135341 is a deficient number, since it is larger than the sum of its proper divisors (926747129939).
115051100135341 is a wasteful number, since it uses less digits than its factorization.
115051100135341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1432496.
The product of its (nonzero) digits is 4500, while the sum is 31.
Adding to 115051100135341 its reverse (143531001150511), we get a palindrome (258582101285852).
The spelling of 115051100135341 in words is "one hundred fifteen trillion, fifty-one billion, one hundred million, one hundred thirty-five thousand, three hundred forty-one".
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