Base | Representation |
---|---|
bin | 10000101111100001101… |
… | …101110010100111011001 |
3 | 11001222202022220120211010 |
4 | 100233201231302213121 |
5 | 122322303021123213 |
6 | 2240315140324133 |
7 | 146060350242453 |
oct | 20574155624731 |
9 | 4058668816733 |
10 | 1150543145433 |
11 | 403a4067a270 |
12 | 166b966a3649 |
13 | 8465a228516 |
14 | 3d987dc12d3 |
15 | 1eddcd82ac3 |
hex | 10be1b729d9 |
1150543145433 has 32 divisors (see below), whose sum is σ = 1675550725632. Its totient is φ = 696452140800.
The previous prime is 1150543145407. The next prime is 1150543145441. The reversal of 1150543145433 is 3345413450511.
It is not a de Polignac number, because 1150543145433 - 26 = 1150543145369 is a prime.
It is a super-2 number, since 2×11505431454332 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1150543145391 and 1150543145400.
It is not an unprimeable number, because it can be changed into a prime (1150543143433) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 132135666 + ... + 132144372.
It is an arithmetic number, because the mean of its divisors is an integer number (52360960176).
Almost surely, 21150543145433 is an apocalyptic number.
It is an amenable number.
1150543145433 is a deficient number, since it is larger than the sum of its proper divisors (525007580199).
1150543145433 is a wasteful number, since it uses less digits than its factorization.
1150543145433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13125.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 1150543145433 its reverse (3345413450511), we get a palindrome (4495956595944).
The spelling of 1150543145433 in words is "one trillion, one hundred fifty billion, five hundred forty-three million, one hundred forty-five thousand, four hundred thirty-three".
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