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1150894113601 = 7914568279919
BaseRepresentation
bin10000101111110110101…
…000101000001101000001
311002000122210022121122011
4100233312220220031001
5122324012343113401
62240414035012521
7146102141361331
oct20576650501501
94060583277564
101150894113601
114041007a5901
1216707413a141
13846b4b602ab
143d9bc8610c1
151ee0daad451
hex10bf6a28341

1150894113601 has 4 divisors (see below), whose sum is σ = 1165462393600. Its totient is φ = 1136325833604.

The previous prime is 1150894113599. The next prime is 1150894113643. The reversal of 1150894113601 is 1063114980511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1150894113601 - 21 = 1150894113599 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1120894113601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7284139881 + ... + 7284140038.

It is an arithmetic number, because the mean of its divisors is an integer number (291365598400).

Almost surely, 21150894113601 is an apocalyptic number.

It is an amenable number.

1150894113601 is a deficient number, since it is larger than the sum of its proper divisors (14568279999).

1150894113601 is an equidigital number, since it uses as much as digits as its factorization.

1150894113601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14568279998.

The product of its (nonzero) digits is 25920, while the sum is 40.

The spelling of 1150894113601 in words is "one trillion, one hundred fifty billion, eight hundred ninety-four million, one hundred thirteen thousand, six hundred one".

Divisors: 1 79 14568279919 1150894113601