11510045413431 has 8 divisors (see below), whose sum is σ = 15349168268544. Its totient is φ = 7672143083640.

The previous prime is 11510045413421. The next prime is 11510045413441. The reversal of 11510045413431 is 13431454001511.

11510045413431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11510045413421) and next prime (11510045413441).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11510045413431 - 2⁹ = 11510045412919 is a prime.

It is a super-2 number, since 2×11510045413431² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11510045413392 and 11510045413401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11510045413411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 305109325 + ... + 305147046.

It is an arithmetic number, because the mean of its divisors is an integer number (1918646033568).

Almost surely, 2^{11510045413431} is an apocalyptic number.

11510045413431 is a deficient number, since it is larger than the sum of its proper divisors (3839122855113).

11510045413431 is an equidigital number, since it uses as much as digits as its factorization.

11510045413431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 610262661.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 11510045413431 its reverse (13431454001511), we get a palindrome (24941499414942).

The spelling of 11510045413431 in words is "eleven trillion, five hundred ten billion, forty-five million, four hundred thirteen thousand, four hundred thirty-one".