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115103340551 = 767315001087
BaseRepresentation
bin110101100110010110…
…0011001100000000111
3102000002202020112112002
41223030230121200013
53341212423344201
6124513332015515
711213240152223
oct1531454314007
9360082215462
10115103340551
11448a6920431
121a383a6159b
13ab1489b944
1457dcca5783
152eda16376b
hex1accb19807

115103340551 has 4 divisors (see below), whose sum is σ = 115118349312. Its totient is φ = 115088331792.

The previous prime is 115103340511. The next prime is 115103340559. The reversal of 115103340551 is 155043301511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155043301511 = 722149043073.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115103340551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115103340559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7492871 + ... + 7508216.

It is an arithmetic number, because the mean of its divisors is an integer number (28779587328).

Almost surely, 2115103340551 is an apocalyptic number.

115103340551 is a deficient number, since it is larger than the sum of its proper divisors (15008761).

115103340551 is an equidigital number, since it uses as much as digits as its factorization.

115103340551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15008760.

The product of its (nonzero) digits is 4500, while the sum is 29.

The spelling of 115103340551 in words is "one hundred fifteen billion, one hundred three million, three hundred forty thousand, five hundred fifty-one".

Divisors: 1 7673 15001087 115103340551