Base | Representation |
---|---|
bin | 110101100110100101… |
… | …0001110110010101101 |
3 | 102000010021221212011112 |
4 | 1223031022032302231 |
5 | 3341221424123010 |
6 | 124514211401405 |
7 | 11213363503331 |
oct | 1531512166255 |
9 | 360107855145 |
10 | 115111161005 |
11 | 44900282015 |
12 | 1a3865b3265 |
13 | ab163a9429 |
14 | 57ddd3d7c1 |
15 | 2edabaaa05 |
hex | 1acd28ecad |
115111161005 has 16 divisors (see below), whose sum is σ = 146320264944. Its totient is φ = 86635560960.
The previous prime is 115111160999. The next prime is 115111161019. The reversal of 115111161005 is 500161111511.
It can be written as a sum of positive squares in 8 ways, for example, as 13638969796 + 101472191209 = 116786^2 + 318547^2 .
It is not a de Polignac number, because 115111161005 - 210 = 115111159981 is a prime.
It is a super-2 number, since 2×1151111610052 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79556 + ... + 486365.
It is an arithmetic number, because the mean of its divisors is an integer number (9145016559).
Almost surely, 2115111161005 is an apocalyptic number.
It is an amenable number.
115111161005 is a deficient number, since it is larger than the sum of its proper divisors (31209103939).
115111161005 is a wasteful number, since it uses less digits than its factorization.
115111161005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 568336.
The product of its (nonzero) digits is 150, while the sum is 23.
Adding to 115111161005 its reverse (500161111511), we get a palindrome (615272272516).
The spelling of 115111161005 in words is "one hundred fifteen billion, one hundred eleven million, one hundred sixty-one thousand, five".
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