1151121533141 has 4 divisors (see below), whose sum is σ = 1151227238784. Its totient is φ = 1151015827500.

The previous prime is 1151121533129. The next prime is 1151121533161. The reversal of 1151121533141 is 1413351211511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1151121533141 is a prime.

It is a super-2 number, since 2×1151121533141² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1151121533161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52836485 + ... + 52858266.

It is an arithmetic number, because the mean of its divisors is an integer number (287806809696).

Almost surely, 2^{1151121533141} is an apocalyptic number.

It is an amenable number.

1151121533141 is a deficient number, since it is larger than the sum of its proper divisors (105705643).

1151121533141 is a wasteful number, since it uses less digits than its factorization.

1151121533141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105705642.

The product of its digits is 1800, while the sum is 29.

Adding to 1151121533141 its reverse (1413351211511), we get a palindrome (2564472744652).

The spelling of 1151121533141 in words is "one trillion, one hundred fifty-one billion, one hundred twenty-one million, five hundred thirty-three thousand, one hundred forty-one".