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115115216041 = 771826328031
BaseRepresentation
bin110101100110101100…
…1101100110010101001
3102000010120120212122001
41223031121230302221
53341223443403131
6124514434331001
711213443122520
oct1531531546251
9360116525561
10115115216041
11449025a1691
121a387a29a61
13ab17199067
1458006b74b7
152edb20c261
hex1acd66cca9

115115216041 has 16 divisors (see below), whose sum is σ = 133434114048. Its totient is φ = 97265221200.

The previous prime is 115115216011. The next prime is 115115216093. The reversal of 115115216041 is 140612511511.

It is not a de Polignac number, because 115115216041 - 29 = 115115215529 is a prime.

It is a super-3 number, since 3×1151152160413 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115115216011) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4092696 + ... + 4120726.

It is an arithmetic number, because the mean of its divisors is an integer number (8339632128).

Almost surely, 2115115216041 is an apocalyptic number.

It is an amenable number.

115115216041 is a deficient number, since it is larger than the sum of its proper divisors (18318898007).

115115216041 is an equidigital number, since it uses as much as digits as its factorization.

115115216041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36372.

The product of its (nonzero) digits is 1200, while the sum is 28.

Adding to 115115216041 its reverse (140612511511), we get a palindrome (255727727552).

The spelling of 115115216041 in words is "one hundred fifteen billion, one hundred fifteen million, two hundred sixteen thousand, forty-one".

Divisors: 1 7 71 497 8263 28031 57841 196217 586673 1990201 4106711 13931407 231620153 1621341071 16445030863 115115216041