Base | Representation |
---|---|
bin | 110101100110101100… |
… | …1101100110011011101 |
3 | 102000010120120212200222 |
4 | 1223031121230303131 |
5 | 3341223443403333 |
6 | 124514434331125 |
7 | 11213443122623 |
oct | 1531531546335 |
9 | 360116525628 |
10 | 115115216093 |
11 | 449025a1729 |
12 | 1a387a29aa5 |
13 | ab171990a7 |
14 | 58006b7513 |
15 | 2edb20c298 |
hex | 1acd66ccdd |
115115216093 has 2 divisors, whose sum is σ = 115115216094. Its totient is φ = 115115216092.
The previous prime is 115115216011. The next prime is 115115216101. The reversal of 115115216093 is 390612511511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111690976804 + 3424239289 = 334202^2 + 58517^2 .
It is a cyclic number.
It is not a de Polignac number, because 115115216093 - 228 = 114846780637 is a prime.
It is a super-2 number, since 2×1151152160932 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115115216693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57557608046 + 57557608047.
It is an arithmetic number, because the mean of its divisors is an integer number (57557608047).
Almost surely, 2115115216093 is an apocalyptic number.
It is an amenable number.
115115216093 is a deficient number, since it is larger than the sum of its proper divisors (1).
115115216093 is an equidigital number, since it uses as much as digits as its factorization.
115115216093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 35.
The spelling of 115115216093 in words is "one hundred fifteen billion, one hundred fifteen million, two hundred sixteen thousand, ninety-three".
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