Base | Representation |
---|---|
bin | 10000110000000110010… |
… | …000111011001001101101 |
3 | 11002001100001201212001201 |
4 | 100300012100323021231 |
5 | 122330032010211323 |
6 | 2240500043205501 |
7 | 146111504254663 |
oct | 20600620731155 |
9 | 4061301655051 |
10 | 1151156335213 |
11 | 404225816885 |
12 | 167127b16891 |
13 | 84727291801 |
14 | 3da055dcc33 |
15 | 1ee26b088ad |
hex | 10c0643b26d |
1151156335213 has 4 divisors (see below), whose sum is σ = 1168337773120. Its totient is φ = 1133974897308.
The previous prime is 1151156335207. The next prime is 1151156335229. The reversal of 1151156335213 is 3125336511511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1151156335213 - 25 = 1151156335181 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1151156335243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8590718853 + ... + 8590718986.
It is an arithmetic number, because the mean of its divisors is an integer number (292084443280).
Almost surely, 21151156335213 is an apocalyptic number.
It is an amenable number.
1151156335213 is a deficient number, since it is larger than the sum of its proper divisors (17181437907).
1151156335213 is an equidigital number, since it uses as much as digits as its factorization.
1151156335213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17181437906.
The product of its digits is 40500, while the sum is 37.
The spelling of 1151156335213 in words is "one trillion, one hundred fifty-one billion, one hundred fifty-six million, three hundred thirty-five thousand, two hundred thirteen".
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