1151205025003 has 4 divisors (see below), whose sum is σ = 1255860027288. Its totient is φ = 1046550022720.

The previous prime is 1151205024979. The next prime is 1151205025007. The reversal of 1151205025003 is 3005205021511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1151205025003 - 2⁹ = 1151205024491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1151205025007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52327501126 + ... + 52327501147.

It is an arithmetic number, because the mean of its divisors is an integer number (313965006822).

Almost surely, 2^{1151205025003} is an apocalyptic number.

1151205025003 is a deficient number, since it is larger than the sum of its proper divisors (104655002285).

1151205025003 is a wasteful number, since it uses less digits than its factorization.

1151205025003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104655002284.

The product of its (nonzero) digits is 1500, while the sum is 25.

The spelling of 1151205025003 in words is "one trillion, one hundred fifty-one billion, two hundred five million, twenty-five thousand, three".