11512113 has 4 divisors (see below), whose sum is σ = 15349488. Its totient is φ = 7674740.

The previous prime is 11512097. The next prime is 11512147. The reversal of 11512113 is 31121511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11512113 - 2⁴ = 11512097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11512092 and 11512101.

It is not an unprimeable number, because it can be changed into a prime (11512013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1918683 + ... + 1918688.

It is an arithmetic number, because the mean of its divisors is an integer number (3837372).

Almost surely, 2^11512113 is an apocalyptic number.

It is an amenable number.

11512113 is a deficient number, since it is larger than the sum of its proper divisors (3837375).

11512113 is an equidigital number, since it uses as much as digits as its factorization.

11512113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3837374.

The product of its digits is 30, while the sum is 15.

The square root of 11512113 is about 3392.9504859340. The cubic root of 11512113 is about 225.7970938371.

Adding to 11512113 its reverse (31121511), we get a palindrome (42633624).

The spelling of 11512113 in words is "eleven million, five hundred twelve thousand, one hundred thirteen".