Base | Representation |
---|---|
bin | 11010001011001111101110… |
… | …101101111010111100010011 |
3 | 120002121120001001111101012001 |
4 | 122023033232231322330103 |
5 | 110042124340420400003 |
6 | 1044502153424014431 |
7 | 33151201545505030 |
oct | 3213175655727423 |
9 | 502546031441161 |
10 | 115122013450003 |
11 | 33754a7640563a |
12 | 10ab3501461417 |
13 | 4c30c61726101 |
14 | 205dd141ca387 |
15 | d498c3a5761d |
hex | 68b3eeb7af13 |
115122013450003 has 32 divisors (see below), whose sum is σ = 136965264468480. Its totient is φ = 94704369315840.
The previous prime is 115122013449917. The next prime is 115122013450019. The reversal of 115122013450003 is 300054310221511.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115122013450003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (115122013450043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9602308 + ... + 17956846.
It is an arithmetic number, because the mean of its divisors is an integer number (4280164514640).
Almost surely, 2115122013450003 is an apocalyptic number.
115122013450003 is a deficient number, since it is larger than the sum of its proper divisors (21843251018477).
115122013450003 is an equidigital number, since it uses as much as digits as its factorization.
115122013450003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8355307.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 115122013450003 its reverse (300054310221511), we get a palindrome (415176323671514).
The spelling of 115122013450003 in words is "one hundred fifteen trillion, one hundred twenty-two billion, thirteen million, four hundred fifty thousand, three".
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