Base | Representation |
---|---|
bin | 1010011110000110110001… |
… | …1001101000110001100111 |
3 | 1111202120100010211202200101 |
4 | 2213201230121220301213 |
5 | 3002104223214410343 |
6 | 40252405235124531 |
7 | 2265511203014605 |
oct | 247415431506147 |
9 | 44676303752611 |
10 | 11512331013223 |
11 | 3739396805127 |
12 | 135b200443747 |
13 | 6567ba172651 |
14 | 2bb2b2340875 |
15 | 14e6deb45e4d |
hex | a786c668c67 |
11512331013223 has 4 divisors (see below), whose sum is σ = 11548647515160. Its totient is φ = 11476014511288.
The previous prime is 11512331013221. The next prime is 11512331013233. The reversal of 11512331013223 is 32231013321511.
11512331013223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11512331013223 - 21 = 11512331013221 is a prime.
It is a super-2 number, since 2×115123310132232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11512331013191 and 11512331013200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11512331013221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18158250493 + ... + 18158251126.
It is an arithmetic number, because the mean of its divisors is an integer number (2887161878790).
Almost surely, 211512331013223 is an apocalyptic number.
11512331013223 is a deficient number, since it is larger than the sum of its proper divisors (36316501937).
11512331013223 is an equidigital number, since it uses as much as digits as its factorization.
11512331013223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36316501936.
The product of its (nonzero) digits is 3240, while the sum is 28.
Adding to 11512331013223 its reverse (32231013321511), we get a palindrome (43743344334734).
The spelling of 11512331013223 in words is "eleven trillion, five hundred twelve billion, three hundred thirty-one million, thirteen thousand, two hundred twenty-three".
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