Search a number
-
+
115123312055 = 523024662411
BaseRepresentation
bin110101100110111100…
…0100101010110110111
3102000011010211012021102
41223031320211112313
53341233031441210
6124515324040315
711213602002203
oct1531570452667
9360133735242
10115123312055
1144907121304
121a38a69309b
13ab18a720bb
1458017c3b03
152edbcaaea5
hex1acde255b7

115123312055 has 4 divisors (see below), whose sum is σ = 138147974472. Its totient is φ = 92098649640.

The previous prime is 115123312001. The next prime is 115123312067. The reversal of 115123312055 is 550213321511.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 115123312055 - 214 = 115123295671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11512331201 + ... + 11512331210.

It is an arithmetic number, because the mean of its divisors is an integer number (34536993618).

Almost surely, 2115123312055 is an apocalyptic number.

115123312055 is a deficient number, since it is larger than the sum of its proper divisors (23024662417).

115123312055 is an equidigital number, since it uses as much as digits as its factorization.

115123312055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23024662416.

The product of its (nonzero) digits is 4500, while the sum is 29.

Adding to 115123312055 its reverse (550213321511), we get a palindrome (665336633566).

The spelling of 115123312055 in words is "one hundred fifteen billion, one hundred twenty-three million, three hundred twelve thousand, fifty-five".

Divisors: 1 5 23024662411 115123312055