Base | Representation |
---|---|
bin | 110101100110111100… |
… | …0100101010110110111 |
3 | 102000011010211012021102 |
4 | 1223031320211112313 |
5 | 3341233031441210 |
6 | 124515324040315 |
7 | 11213602002203 |
oct | 1531570452667 |
9 | 360133735242 |
10 | 115123312055 |
11 | 44907121304 |
12 | 1a38a69309b |
13 | ab18a720bb |
14 | 58017c3b03 |
15 | 2edbcaaea5 |
hex | 1acde255b7 |
115123312055 has 4 divisors (see below), whose sum is σ = 138147974472. Its totient is φ = 92098649640.
The previous prime is 115123312001. The next prime is 115123312067. The reversal of 115123312055 is 550213321511.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 115123312055 - 214 = 115123295671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11512331201 + ... + 11512331210.
It is an arithmetic number, because the mean of its divisors is an integer number (34536993618).
Almost surely, 2115123312055 is an apocalyptic number.
115123312055 is a deficient number, since it is larger than the sum of its proper divisors (23024662417).
115123312055 is an equidigital number, since it uses as much as digits as its factorization.
115123312055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23024662416.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 115123312055 its reverse (550213321511), we get a palindrome (665336633566).
The spelling of 115123312055 in words is "one hundred fifteen billion, one hundred twenty-three million, three hundred twelve thousand, fifty-five".
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