115124034200313 has 4 divisors (see below), whose sum is σ = 153498712267088. Its totient is φ = 76749356133540.

The previous prime is 115124034200281. The next prime is 115124034200333. The reversal of 115124034200313 is 313002430421511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 115124034200313 - 2⁵ = 115124034200281 is a prime.

It is a super-3 number, since 3×115124034200313³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115124034200333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19187339033383 + ... + 19187339033388.

It is an arithmetic number, because the mean of its divisors is an integer number (38374678066772).

Almost surely, 2^{115124034200313} is an apocalyptic number.

It is an amenable number.

115124034200313 is a deficient number, since it is larger than the sum of its proper divisors (38374678066775).

115124034200313 is an equidigital number, since it uses as much as digits as its factorization.

115124034200313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38374678066774.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 115124034200313 its reverse (313002430421511), we get a palindrome (428126464621824).

The spelling of 115124034200313 in words is "one hundred fifteen trillion, one hundred twenty-four billion, thirty-four million, two hundred thousand, three hundred thirteen".