Base | Representation |
---|---|
bin | 1010011110001001010100… |
… | …0011101010110000000000 |
3 | 1111202122002200100101021100 |
4 | 2213202111003222300000 |
5 | 3002112122324320000 |
6 | 40253001043054400 |
7 | 2265534124563240 |
oct | 247422503526000 |
9 | 44678080311240 |
10 | 11513013120000 |
11 | 3739706843037 |
12 | 135b370971400 |
13 | 656898588522 |
14 | 2bb338b7bb20 |
15 | 14e72e981a00 |
hex | a78950eac00 |
11513013120000 has 2640 divisors, whose sum is σ = 50140362747904. Its totient is φ = 2488320000000.
The previous prime is 11513013119999. The next prime is 11513013120013. The reversal of 11513013120000 is 2131031511.
11513013120000 is a `hidden beast` number, since 1 + 1 + 51 + 301 + 312 + 0 + 0 + 0 + 0 = 666.
It is a super-2 number, since 2×115130131200002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 76245119925 + ... + 76245120075.
Almost surely, 211513013120000 is an apocalyptic number.
11513013120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11513013120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25070181373952).
11513013120000 is an abundant number, since it is smaller than the sum of its proper divisors (38627349627904).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11513013120000 is a wasteful number, since it uses less digits than its factorization.
11513013120000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 296 (or 260 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 11513013120000 its reverse (2131031511), we get a palindrome (11515144151511).
The spelling of 11513013120000 in words is "eleven trillion, five hundred thirteen billion, thirteen million, one hundred twenty thousand".
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