11513111330051 has 4 divisors (see below), whose sum is σ = 11758071145632. Its totient is φ = 11268151514472.

The previous prime is 11513111330047. The next prime is 11513111330059. The reversal of 11513111330051 is 15003311131511.

11513111330051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11513111330051 - 2² = 11513111330047 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11513111330051.

It is not an unprimeable number, because it can be changed into a prime (11513111330059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122479907720 + ... + 122479907813.

It is an arithmetic number, because the mean of its divisors is an integer number (2939517786408).

Almost surely, 2^{11513111330051} is an apocalyptic number.

11513111330051 is a deficient number, since it is larger than the sum of its proper divisors (244959815581).

11513111330051 is an equidigital number, since it uses as much as digits as its factorization.

11513111330051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244959815580.

The product of its (nonzero) digits is 675, while the sum is 26.

Adding to 11513111330051 its reverse (15003311131511), we get a palindrome (26516422461562).

The spelling of 11513111330051 in words is "eleven trillion, five hundred thirteen billion, one hundred eleven million, three hundred thirty thousand, fifty-one".