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11513160220245 = 357310514301571
BaseRepresentation
bin1010011110001001110111…
…0100110011111001010101
31111202122110221010211212120
42213202131310303321111
53002112423004021440
640253023420010153
72265540562115025
oct247423564637125
944678427124776
1011513160220245
113739781884692
12135b3b2090959
136568bcbb05a8
142bb35050da85
1514e73c83bdd0
hexa789dd33e55

11513160220245 has 16 divisors (see below), whose sum is σ = 18673399591872. Its totient is φ = 6056237704320.

The previous prime is 11513160220223. The next prime is 11513160220253. The reversal of 11513160220245 is 54202206131511.

It is not a de Polignac number, because 11513160220245 - 218 = 11513159958101 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5257149691 + ... + 5257151880.

It is an arithmetic number, because the mean of its divisors is an integer number (1167087474492).

Almost surely, 211513160220245 is an apocalyptic number.

11513160220245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11513160220245 is a deficient number, since it is larger than the sum of its proper divisors (7160239371627).

11513160220245 is a wasteful number, since it uses less digits than its factorization.

11513160220245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10514301652.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 11513160220245 its reverse (54202206131511), we get a palindrome (65715366351756).

The spelling of 11513160220245 in words is "eleven trillion, five hundred thirteen billion, one hundred sixty million, two hundred twenty thousand, two hundred forty-five".

Divisors: 1 3 5 15 73 219 365 1095 10514301571 31542904713 52571507855 157714523565 767544014683 2302632044049 3837720073415 11513160220245