Base | Representation |
---|---|
bin | 1010011110001001110111… |
… | …0100110011111001010111 |
3 | 1111202122110221010211212122 |
4 | 2213202131310303321113 |
5 | 3002112423004021442 |
6 | 40253023420010155 |
7 | 2265540562115030 |
oct | 247423564637127 |
9 | 44678427124778 |
10 | 11513160220247 |
11 | 3739781884694 |
12 | 135b3b209095b |
13 | 6568bcbb05aa |
14 | 2bb35050da87 |
15 | 14e73c83bdd2 |
hex | a789dd33e57 |
11513160220247 has 8 divisors (see below), whose sum is σ = 13729979890176. Its totient is φ = 9439361174232.
The previous prime is 11513160220223. The next prime is 11513160220253. The reversal of 11513160220247 is 74202206131511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11513160220247 - 26 = 11513160220183 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11513160270247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35755155803 + ... + 35755156124.
It is an arithmetic number, because the mean of its divisors is an integer number (1716247486272).
Almost surely, 211513160220247 is an apocalyptic number.
11513160220247 is a deficient number, since it is larger than the sum of its proper divisors (2216819669929).
11513160220247 is an equidigital number, since it uses as much as digits as its factorization.
11513160220247 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71510311957.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 11513160220247 its reverse (74202206131511), we get a palindrome (85715366351758).
The spelling of 11513160220247 in words is "eleven trillion, five hundred thirteen billion, one hundred sixty million, two hundred twenty thousand, two hundred forty-seven".
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