Search a number
-
+
115132103 = 276741609
BaseRepresentation
bin1101101110011…
…00011011000111
322000122022112222
412313030123013
5213433211403
615231402555
72565415052
oct667143307
9260568488
10115132103
1159a974a9
123268345b
131ab11308
141140da99
15a193338
hex6dcc6c7

115132103 has 4 divisors (see below), whose sum is σ = 115176480. Its totient is φ = 115087728.

The previous prime is 115132099. The next prime is 115132111. The reversal of 115132103 is 301231511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115132103 - 22 = 115132099 is a prime.

It is a super-2 number, since 2×1151321032 = 26510802282405218, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115132403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18038 + ... + 23571.

It is an arithmetic number, because the mean of its divisors is an integer number (28794120).

Almost surely, 2115132103 is an apocalyptic number.

115132103 is a deficient number, since it is larger than the sum of its proper divisors (44377).

115132103 is an equidigital number, since it uses as much as digits as its factorization.

115132103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44376.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 115132103 is about 10729.9628610727. The cubic root of 115132103 is about 486.4805475101.

Adding to 115132103 its reverse (301231511), we get a palindrome (416363614).

The spelling of 115132103 in words is "one hundred fifteen million, one hundred thirty-two thousand, one hundred three".

Divisors: 1 2767 41609 115132103