11514012431 has 4 divisors (see below), whose sum is σ = 11514246672. Its totient is φ = 11513778192.

The previous prime is 11514012397. The next prime is 11514012437. The reversal of 11514012431 is 13421041511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11514012431 - 2¹⁴ = 11513996047 is a prime.

It is a super-2 number, since 2×11514012431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11514012397 and 11514012406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11514012437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11846 + ... + 152211.

It is an arithmetic number, because the mean of its divisors is an integer number (2878561668).

Almost surely, 2^11514012431 is an apocalyptic number.

11514012431 is a deficient number, since it is larger than the sum of its proper divisors (234241).

11514012431 is an equidigital number, since it uses as much as digits as its factorization.

11514012431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 234240.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 11514012431 its reverse (13421041511), we get a palindrome (24935053942).

The spelling of 11514012431 in words is "eleven billion, five hundred fourteen million, twelve thousand, four hundred thirty-one".