Search a number
-
+
115143112207 = 595527353099
BaseRepresentation
bin110101100111100010…
…0000111011000001111
3102000012112002010222101
41223033010013120033
53341303114042312
6124521312255531
711214232206454
oct1531704073017
9360175063871
10115143112207
1144917315472
121a3952415a7
13ab1cbb5576
14580429982b
152edd8bca57
hex1acf10760f

115143112207 has 8 divisors (see below), whose sum is σ = 117116208000. Its totient is φ = 113170733784.

The previous prime is 115143112163. The next prime is 115143112213. The reversal of 115143112207 is 702211341511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115143112207 - 215 = 115143079439 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115143112247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 149544 + ... + 502642.

It is an arithmetic number, because the mean of its divisors is an integer number (14639526000).

Almost surely, 2115143112207 is an apocalyptic number.

115143112207 is a deficient number, since it is larger than the sum of its proper divisors (1973095793).

115143112207 is an equidigital number, since it uses as much as digits as its factorization.

115143112207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 358685.

The product of its (nonzero) digits is 1680, while the sum is 28.

Adding to 115143112207 its reverse (702211341511), we get a palindrome (817354453718).

The spelling of 115143112207 in words is "one hundred fifteen billion, one hundred forty-three million, one hundred twelve thousand, two hundred seven".

Divisors: 1 59 5527 326093 353099 20832841 1951578173 115143112207