Base | Representation |
---|---|
bin | 110101100111100010… |
… | …0000111011000001111 |
3 | 102000012112002010222101 |
4 | 1223033010013120033 |
5 | 3341303114042312 |
6 | 124521312255531 |
7 | 11214232206454 |
oct | 1531704073017 |
9 | 360175063871 |
10 | 115143112207 |
11 | 44917315472 |
12 | 1a3952415a7 |
13 | ab1cbb5576 |
14 | 580429982b |
15 | 2edd8bca57 |
hex | 1acf10760f |
115143112207 has 8 divisors (see below), whose sum is σ = 117116208000. Its totient is φ = 113170733784.
The previous prime is 115143112163. The next prime is 115143112213. The reversal of 115143112207 is 702211341511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 115143112207 - 215 = 115143079439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115143112247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 149544 + ... + 502642.
It is an arithmetic number, because the mean of its divisors is an integer number (14639526000).
Almost surely, 2115143112207 is an apocalyptic number.
115143112207 is a deficient number, since it is larger than the sum of its proper divisors (1973095793).
115143112207 is an equidigital number, since it uses as much as digits as its factorization.
115143112207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 358685.
The product of its (nonzero) digits is 1680, while the sum is 28.
Adding to 115143112207 its reverse (702211341511), we get a palindrome (817354453718).
The spelling of 115143112207 in words is "one hundred fifteen billion, one hundred forty-three million, one hundred twelve thousand, two hundred seven".
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