115146717503651 has 4 divisors (see below), whose sum is σ = 115853139083592. Its totient is φ = 114440295923712.

The previous prime is 115146717503611. The next prime is 115146717503669. The reversal of 115146717503651 is 156305717641511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115146717503651 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115146717503593 and 115146717503602.

It is not an unprimeable number, because it can be changed into a prime (115146717503611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353210789726 + ... + 353210790051.

It is an arithmetic number, because the mean of its divisors is an integer number (28963284770898).

Almost surely, 2^{115146717503651} is an apocalyptic number.

115146717503651 is a deficient number, since it is larger than the sum of its proper divisors (706421579941).

115146717503651 is an equidigital number, since it uses as much as digits as its factorization.

115146717503651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 706421579940.

The product of its (nonzero) digits is 2646000, while the sum is 53.

The spelling of 115146717503651 in words is "one hundred fifteen trillion, one hundred forty-six billion, seven hundred seventeen million, five hundred three thousand, six hundred fifty-one".