Base | Representation |
---|---|
bin | 1010011110010000110000… |
… | …0101101010000010000111 |
3 | 1111202211020212002000001201 |
4 | 2213210030011222002013 |
5 | 3002130220043130210 |
6 | 40253531142003331 |
7 | 2265634454103055 |
oct | 247441405520207 |
9 | 44684225060051 |
10 | 11515010130055 |
11 | 373a541028273 |
12 | 135b829716547 |
13 | 656b26226993 |
14 | 2bb4880991d5 |
15 | 14e7e9e5353a |
hex | a790c16a087 |
11515010130055 has 8 divisors (see below), whose sum is σ = 13877316930672. Its totient is φ = 9172471587648.
The previous prime is 11515010130047. The next prime is 11515010130227. The reversal of 11515010130055 is 55003101051511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11515010130055 - 23 = 11515010130047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4942063269 + ... + 4942065598.
It is an arithmetic number, because the mean of its divisors is an integer number (1734664616334).
Almost surely, 211515010130055 is an apocalyptic number.
11515010130055 is a deficient number, since it is larger than the sum of its proper divisors (2362306800617).
11515010130055 is an equidigital number, since it uses as much as digits as its factorization.
11515010130055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9884129105.
The product of its (nonzero) digits is 1875, while the sum is 28.
Adding to 11515010130055 its reverse (55003101051511), we get a palindrome (66518111181566).
The spelling of 11515010130055 in words is "eleven trillion, five hundred fifteen billion, ten million, one hundred thirty thousand, fifty-five".
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