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11520010133 = 73915588647
BaseRepresentation
bin10101011101010010…
…10110011110010101
31002201211221011000222
422232221112132111
5142043110311013
65143041444125
7555322320242
oct125651263625
932654834028
1011520010133
114981822135
122296040645
131117897658
147b3d945c9
1547655b508
hex2aea56795

11520010133 has 4 divisors (see below), whose sum is σ = 11535599520. Its totient is φ = 11504420748.

The previous prime is 11520010129. The next prime is 11520010157. The reversal of 11520010133 is 33101002511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11520010133 - 22 = 11520010129 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11520010123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7793585 + ... + 7795062.

It is an arithmetic number, because the mean of its divisors is an integer number (2883899880).

Almost surely, 211520010133 is an apocalyptic number.

It is an amenable number.

11520010133 is a deficient number, since it is larger than the sum of its proper divisors (15589387).

11520010133 is an equidigital number, since it uses as much as digits as its factorization.

11520010133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15589386.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 11520010133 its reverse (33101002511), we get a palindrome (44621012644).

The spelling of 11520010133 in words is "eleven billion, five hundred twenty million, ten thousand, one hundred thirty-three".

Divisors: 1 739 15588647 11520010133