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115200351313 = 1091056883957
BaseRepresentation
bin110101101001001111…
…0011101110001010001
3102000100111210012021021
41223102132131301101
53341412242220223
6124531115155441
711215525554355
oct1532236356121
9360314705237
10115200351313
1144946660013
121a3b0445b81
13ab2ba06968
14580bb19465
152ee392765d
hex1ad279dc51

115200351313 has 4 divisors (see below), whose sum is σ = 116257235380. Its totient is φ = 114143467248.

The previous prime is 115200351311. The next prime is 115200351323. The reversal of 115200351313 is 313153002511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 41269109904 + 73931241409 = 203148^2 + 271903^2 .

It is a cyclic number.

It is not a de Polignac number, because 115200351313 - 21 = 115200351311 is a prime.

It is a super-2 number, since 2×1152003513132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115200351311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 528441870 + ... + 528442087.

It is an arithmetic number, because the mean of its divisors is an integer number (29064308845).

Almost surely, 2115200351313 is an apocalyptic number.

It is an amenable number.

115200351313 is a deficient number, since it is larger than the sum of its proper divisors (1056884067).

115200351313 is a wasteful number, since it uses less digits than its factorization.

115200351313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1056884066.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 115200351313 its reverse (313153002511), we get a palindrome (428353353824).

The spelling of 115200351313 in words is "one hundred fifteen billion, two hundred million, three hundred fifty-one thousand, three hundred thirteen".

Divisors: 1 109 1056883957 115200351313