115200357403 has 4 divisors (see below), whose sum is σ = 115836823648. Its totient is φ = 114563891160.

The previous prime is 115200357383. The next prime is 115200357457. The reversal of 115200357403 is 304753002511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304753002511 = 3529 ⋅86356759.

It is a cyclic number.

It is not a de Polignac number, because 115200357403 - 2¹³ = 115200349211 is a prime.

It is a super-2 number, since 2×115200357403² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115200357203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318232851 + ... + 318233212.

It is an arithmetic number, because the mean of its divisors is an integer number (28959205912).

Almost surely, 2^115200357403 is an apocalyptic number.

115200357403 is a deficient number, since it is larger than the sum of its proper divisors (636466245).

115200357403 is an equidigital number, since it uses as much as digits as its factorization.

115200357403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 636466244.

The product of its (nonzero) digits is 12600, while the sum is 31.

Adding to 115200357403 its reverse (304753002511), we get a palindrome (419953359914).

The spelling of 115200357403 in words is "one hundred fifteen billion, two hundred million, three hundred fifty-seven thousand, four hundred three".