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115200635143 = 1110472785013
BaseRepresentation
bin110101101001001111…
…1100011000100000111
3102000100112022121121111
41223102133203010013
53341412330311033
6124531125225451
711215531146016
oct1532237430407
9360315277544
10115200635143
1144946834290
121a3b0562287
13ab2baa5bc9
14580bb90a7d
152ee39817cd
hex1ad27e3107

115200635143 has 4 divisors (see below), whose sum is σ = 125673420168. Its totient is φ = 104727850120.

The previous prime is 115200635131. The next prime is 115200635161. The reversal of 115200635143 is 341536002511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115200635143 - 229 = 114663764231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115200635743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5236392496 + ... + 5236392517.

It is an arithmetic number, because the mean of its divisors is an integer number (31418355042).

Almost surely, 2115200635143 is an apocalyptic number.

115200635143 is a deficient number, since it is larger than the sum of its proper divisors (10472785025).

115200635143 is a wasteful number, since it uses less digits than its factorization.

115200635143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10472785024.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 115200635143 its reverse (341536002511), we get a palindrome (456736637654).

The spelling of 115200635143 in words is "one hundred fifteen billion, two hundred million, six hundred thirty-five thousand, one hundred forty-three".

Divisors: 1 11 10472785013 115200635143