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11521134341 = 17964363879
BaseRepresentation
bin10101011101011011…
…01000111100000101
31002201221001021011022
422232231220330011
5142043402244331
65143121520525
7555335011643
oct125655507405
932657037138
1011521134341
11498241a832
1222964a3145
131117b9c272
147b41a8193
154766ce67b
hex2aeb68f05

11521134341 has 4 divisors (see below), whose sum is σ = 11585498400. Its totient is φ = 11456770284.

The previous prime is 11521134307. The next prime is 11521134347. The reversal of 11521134341 is 14343112511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11521134341 - 210 = 11521133317 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11521134341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11521134347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32181761 + ... + 32182118.

It is an arithmetic number, because the mean of its divisors is an integer number (2896374600).

Almost surely, 211521134341 is an apocalyptic number.

It is an amenable number.

11521134341 is a deficient number, since it is larger than the sum of its proper divisors (64364059).

11521134341 is an equidigital number, since it uses as much as digits as its factorization.

11521134341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64364058.

The product of its digits is 1440, while the sum is 26.

Adding to 11521134341 its reverse (14343112511), we get a palindrome (25864246852).

The spelling of 11521134341 in words is "eleven billion, five hundred twenty-one million, one hundred thirty-four thousand, three hundred forty-one".

Divisors: 1 179 64363879 11521134341