Base | Representation |
---|---|
bin | 11010001100100011000100… |
… | …100010110010110001101010 |
3 | 120002221010000112121102221100 |
4 | 122030203010202302301222 |
5 | 110100111123022444424 |
6 | 1045011233231422230 |
7 | 33160520243403000 |
oct | 3214430442626152 |
9 | 502833015542840 |
10 | 115211500203114 |
11 | 33789a17341747 |
12 | 10b08916384976 |
13 | 4c395231058b3 |
14 | 20643a2c84a70 |
15 | d4bdaed00dc9 |
hex | 68c8c48b2c6a |
115211500203114 has 48 divisors (see below), whose sum is σ = 291107775067200. Its totient is φ = 32917571484840.
The previous prime is 115211500203071. The next prime is 115211500203133. The reversal of 115211500203114 is 411302005112511.
115211500203114 is a `hidden beast` number, since 1 + 1 + 5 + 21 + 1 + 500 + 20 + 3 + 114 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9330371232 + ... + 9330383579.
It is an arithmetic number, because the mean of its divisors is an integer number (6064745313900).
Almost surely, 2115211500203114 is an apocalyptic number.
115211500203114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
115211500203114 is an abundant number, since it is smaller than the sum of its proper divisors (175896274864086).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115211500203114 is a wasteful number, since it uses less digits than its factorization.
115211500203114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18660754840 (or 18660754823 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 27.
Adding to 115211500203114 its reverse (411302005112511), we get a palindrome (526513505315625).
The spelling of 115211500203114 in words is "one hundred fifteen trillion, two hundred eleven billion, five hundred million, two hundred three thousand, one hundred fourteen".
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