Base | Representation |
---|---|
bin | 110101101001100111… |
… | …1001110101000000111 |
3 | 102000101101211122021211 |
4 | 1223103033032220013 |
5 | 3341424030244333 |
6 | 124532253152251 |
7 | 11216042324566 |
oct | 1532317165007 |
9 | 360341748254 |
10 | 115213134343 |
11 | 449528a10aa |
12 | 1a3b478b687 |
13 | ab31561198 |
14 | 580d6c5bdd |
15 | 2ee4aeeecd |
hex | 1ad33cea07 |
115213134343 has 4 divisors (see below), whose sum is σ = 115222133448. Its totient is φ = 115204135240.
The previous prime is 115213134313. The next prime is 115213134431. The reversal of 115213134343 is 343431312511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115213134343 - 221 = 115211037191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115213134313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4480321 + ... + 4505962.
It is an arithmetic number, because the mean of its divisors is an integer number (28805533362).
Almost surely, 2115213134343 is an apocalyptic number.
115213134343 is a deficient number, since it is larger than the sum of its proper divisors (8999105).
115213134343 is an equidigital number, since it uses as much as digits as its factorization.
115213134343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8999104.
The product of its digits is 12960, while the sum is 31.
Adding to 115213134343 its reverse (343431312511), we get a palindrome (458644446854).
The spelling of 115213134343 in words is "one hundred fifteen billion, two hundred thirteen million, one hundred thirty-four thousand, three hundred forty-three".
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