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115213443150154 = 257606721575077
BaseRepresentation
bin11010001100100100111000…
…010110100011000101001010
3120002221022000221121101012211
4122030210320112203011022
5110100124112421301104
61045012154115455334
733160616345233426
oct3214447026430512
9502838027541184
10115213443150154
113378a8240605a8
1210b09178bb754a
134c397727c54bb
142064508d2bb86
15d4be75693e04
hex68c9385a314a

115213443150154 has 4 divisors (see below), whose sum is σ = 172820164725234. Its totient is φ = 57606721575076.

The previous prime is 115213443150151. The next prime is 115213443150187. The reversal of 115213443150154 is 451051344312511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 105484751912929 + 9728691237225 = 10270577^2 + 3119085^2 .

It is not an unprimeable number, because it can be changed into a prime (115213443150151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28803360787537 + ... + 28803360787540.

Almost surely, 2115213443150154 is an apocalyptic number.

115213443150154 is a deficient number, since it is larger than the sum of its proper divisors (57606721575080).

115213443150154 is an equidigital number, since it uses as much as digits as its factorization.

115213443150154 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57606721575079.

The product of its (nonzero) digits is 144000, while the sum is 40.

Adding to 115213443150154 its reverse (451051344312511), we get a palindrome (566264787462665).

The spelling of 115213443150154 in words is "one hundred fifteen trillion, two hundred thirteen billion, four hundred forty-three million, one hundred fifty thousand, one hundred fifty-four".

Divisors: 1 2 57606721575077 115213443150154