Base | Representation |
---|---|
bin | 1010011110101100101011… |
… | …0110011010100011100111 |
3 | 1111210112121020000210022212 |
4 | 2213223022312122203213 |
5 | 3002241042410100210 |
6 | 40301211014514035 |
7 | 2266321300112363 |
oct | 247531266324347 |
9 | 44715536023285 |
10 | 11522505550055 |
11 | 3742737aa0255 |
12 | 136117b96591b |
13 | 65774c070146 |
14 | 2bb9997382a3 |
15 | 14ead7ecd805 |
hex | a7acad9a8e7 |
11522505550055 has 16 divisors (see below), whose sum is σ = 13984751865600. Its totient is φ = 9112876312320.
The previous prime is 11522505550033. The next prime is 11522505550063. The reversal of 11522505550055 is 55005550522511.
It is not a de Polignac number, because 11522505550055 - 218 = 11522505287911 is a prime.
It is a super-2 number, since 2×115225055500552 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11522505549994 and 11522505550021.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 405770 + ... + 4817640.
It is an arithmetic number, because the mean of its divisors is an integer number (874046991600).
Almost surely, 211522505550055 is an apocalyptic number.
11522505550055 is a deficient number, since it is larger than the sum of its proper divisors (2462246315545).
11522505550055 is an equidigital number, since it uses as much as digits as its factorization.
11522505550055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4417834.
The product of its (nonzero) digits is 312500, while the sum is 41.
The spelling of 11522505550055 in words is "eleven trillion, five hundred twenty-two billion, five hundred five million, five hundred fifty thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •