Base | Representation |
---|---|
bin | 11010001100110100100101… |
… | …101110011101100111100011 |
3 | 120002222220120110112121120020 |
4 | 122030310211232131213203 |
5 | 110100413133443140230 |
6 | 1045024023542044523 |
7 | 33162054341434563 |
oct | 3214644556354743 |
9 | 502886513477506 |
10 | 115230310521315 |
11 | 3379699a272170 |
12 | 10b104a5a19743 |
13 | 4c3b23018c6b2 |
14 | 2065269164da3 |
15 | d4c6113bd810 |
hex | 68cd25b9d9e3 |
115230310521315 has 32 divisors (see below), whose sum is σ = 201133072809216. Its totient is φ = 55868184927360.
The previous prime is 115230310521301. The next prime is 115230310521421. The reversal of 115230310521315 is 513125013032511.
It is not a de Polignac number, because 115230310521315 - 25 = 115230310521283 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2183532 + ... + 15337158.
It is an arithmetic number, because the mean of its divisors is an integer number (6285408525288).
Almost surely, 2115230310521315 is an apocalyptic number.
115230310521315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115230310521315 is a deficient number, since it is larger than the sum of its proper divisors (85902762287901).
115230310521315 is a wasteful number, since it uses less digits than its factorization.
115230310521315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13206739.
The product of its (nonzero) digits is 13500, while the sum is 33.
Adding to 115230310521315 its reverse (513125013032511), we get a palindrome (628355323553826).
The spelling of 115230310521315 in words is "one hundred fifteen trillion, two hundred thirty billion, three hundred ten million, five hundred twenty-one thousand, three hundred fifteen".
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