Base | Representation |
---|---|
bin | 11010001100110100100111… |
… | …101110010101000001100001 |
3 | 120002222220122210121120022012 |
4 | 122030310213232111001201 |
5 | 110100413221033244140 |
6 | 1045024031140322305 |
7 | 33162055226361356 |
oct | 3214644756250141 |
9 | 502886583546265 |
10 | 115230344040545 |
11 | 33796a07186708 |
12 | 10b104b50a3395 |
13 | 4c3b2370c7466 |
14 | 206526d7ac62d |
15 | d4c6142e0265 |
hex | 68cd27b95061 |
115230344040545 has 4 divisors (see below), whose sum is σ = 138276412848660. Its totient is φ = 92184275232432.
The previous prime is 115230344040503. The next prime is 115230344040619. The reversal of 115230344040545 is 545040443032511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 63397011026176 + 51833333014369 = 7962224^2 + 7199537^2 .
It is a cyclic number.
It is not a de Polignac number, because 115230344040545 - 216 = 115230343975009 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11523034404050 + ... + 11523034404059.
It is an arithmetic number, because the mean of its divisors is an integer number (34569103212165).
Almost surely, 2115230344040545 is an apocalyptic number.
It is an amenable number.
115230344040545 is a deficient number, since it is larger than the sum of its proper divisors (23046068808115).
115230344040545 is an equidigital number, since it uses as much as digits as its factorization.
115230344040545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23046068808114.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 115230344040545 in words is "one hundred fifteen trillion, two hundred thirty billion, three hundred forty-four million, forty thousand, five hundred forty-five".
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