Base | Representation |
---|---|
bin | 11010001100110100100111… |
… | …101110010101000010101011 |
3 | 120002222220122210121120101221 |
4 | 122030310213232111002223 |
5 | 110100413221033244434 |
6 | 1045024031140322511 |
7 | 33162055226361523 |
oct | 3214644756250253 |
9 | 502886583546357 |
10 | 115230344040619 |
11 | 33796a07186775 |
12 | 10b104b50a3437 |
13 | 4c3b2370c74c2 |
14 | 206526d7ac683 |
15 | d4c6142e02b4 |
hex | 68cd27b950ab |
115230344040619 has 2 divisors, whose sum is σ = 115230344040620. Its totient is φ = 115230344040618.
The previous prime is 115230344040503. The next prime is 115230344040697. The reversal of 115230344040619 is 916040443032511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115230344040619 - 211 = 115230344038571 is a prime.
It is a super-2 number, since 2×1152303440406192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115230344044619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615172020309 + 57615172020310.
It is an arithmetic number, because the mean of its divisors is an integer number (57615172020310).
Almost surely, 2115230344040619 is an apocalyptic number.
115230344040619 is a deficient number, since it is larger than the sum of its proper divisors (1).
115230344040619 is an equidigital number, since it uses as much as digits as its factorization.
115230344040619 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 115230344040619 in words is "one hundred fifteen trillion, two hundred thirty billion, three hundred forty-four million, forty thousand, six hundred nineteen".
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