115230423525041 has 4 divisors (see below), whose sum is σ = 125705916572784. Its totient is φ = 104754930477300.

The previous prime is 115230423525011. The next prime is 115230423525047. The reversal of 115230423525041 is 140525324032511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115230423525041 - 2³⁴ = 115213243655857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115230423524986 and 115230423525004.

It is not an unprimeable number, because it can be changed into a prime (115230423525047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5237746523855 + ... + 5237746523876.

It is an arithmetic number, because the mean of its divisors is an integer number (31426479143196).

Almost surely, 2^{115230423525041} is an apocalyptic number.

115230423525041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

115230423525041 is a deficient number, since it is larger than the sum of its proper divisors (10475493047743).

115230423525041 is a wasteful number, since it uses less digits than its factorization.

115230423525041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10475493047742.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 115230423525041 its reverse (140525324032511), we get a palindrome (255755747557552).

The spelling of 115230423525041 in words is "one hundred fifteen trillion, two hundred thirty billion, four hundred twenty-three million, five hundred twenty-five thousand, forty-one".