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115230433021251 = 3311274239723809
BaseRepresentation
bin11010001100110100101101…
…000001110000110101000011
3120002222220220000001020212220
4122030310231001300311003
5110100413411323140001
61045024044035422123
733162060356610342
oct3214645501606503
9502886800036786
10115230433021251
1133796a52431189
1210b1051aa54943
134c3b24c680472
14206527b531b59
15d4c61c019c36
hex68cd2d070d43

115230433021251 has 16 divisors (see below), whose sum is σ = 158597985976320. Its totient is φ = 74341623778560.

The previous prime is 115230433021247. The next prime is 115230433021261. The reversal of 115230433021251 is 152120334032511.

It is a happy number.

It is not a de Polignac number, because 115230433021251 - 22 = 115230433021247 is a prime.

It is not an unprimeable number, because it can be changed into a prime (115230433021261) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6988435 + ... + 16712243.

It is an arithmetic number, because the mean of its divisors is an integer number (9912374123520).

Almost surely, 2115230433021251 is an apocalyptic number.

115230433021251 is a deficient number, since it is larger than the sum of its proper divisors (43367552955069).

115230433021251 is a wasteful number, since it uses less digits than its factorization.

115230433021251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9851266.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 115230433021251 its reverse (152120334032511), we get a palindrome (267350767053762).

The spelling of 115230433021251 in words is "one hundred fifteen trillion, two hundred thirty billion, four hundred thirty-three million, twenty-one thousand, two hundred fifty-one".

Divisors: 1 3 31 93 127423 382269 3950113 9723809 11850339 29171427 301438079 904314237 1239036914207 3717110742621 38410144340417 115230433021251