Base | Representation |
---|---|
bin | 110101101010001000… |
… | …1101100111100110101 |
3 | 102000102121121221212111 |
4 | 1223110101230330311 |
5 | 3341443010410203 |
6 | 124534114451021 |
7 | 11216343412450 |
oct | 1532421547465 |
9 | 360377557774 |
10 | 115230560053 |
11 | 44961713314 |
12 | 1a3ba593a71 |
13 | ab3505295b |
14 | 5811b40497 |
15 | 2ee63e326d |
hex | 1ad446cf35 |
115230560053 has 8 divisors (see below), whose sum is σ = 131746982400. Its totient is φ = 98727866160.
The previous prime is 115230560051. The next prime is 115230560077. The reversal of 115230560053 is 350065032511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 115230560053 - 21 = 115230560051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115230559997 and 115230560024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115230560051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3414118 + ... + 3447703.
It is an arithmetic number, because the mean of its divisors is an integer number (16468372800).
Almost surely, 2115230560053 is an apocalyptic number.
It is an amenable number.
115230560053 is a deficient number, since it is larger than the sum of its proper divisors (16516422347).
115230560053 is an equidigital number, since it uses as much as digits as its factorization.
115230560053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6864227.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 115230560053 its reverse (350065032511), we get a palindrome (465295592564).
The spelling of 115230560053 in words is "one hundred fifteen billion, two hundred thirty million, five hundred sixty thousand, fifty-three".
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