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115230560053 = 723996861821
BaseRepresentation
bin110101101010001000…
…1101100111100110101
3102000102121121221212111
41223110101230330311
53341443010410203
6124534114451021
711216343412450
oct1532421547465
9360377557774
10115230560053
1144961713314
121a3ba593a71
13ab3505295b
145811b40497
152ee63e326d
hex1ad446cf35

115230560053 has 8 divisors (see below), whose sum is σ = 131746982400. Its totient is φ = 98727866160.

The previous prime is 115230560051. The next prime is 115230560077. The reversal of 115230560053 is 350065032511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 115230560053 - 21 = 115230560051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115230559997 and 115230560024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115230560051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3414118 + ... + 3447703.

It is an arithmetic number, because the mean of its divisors is an integer number (16468372800).

Almost surely, 2115230560053 is an apocalyptic number.

It is an amenable number.

115230560053 is a deficient number, since it is larger than the sum of its proper divisors (16516422347).

115230560053 is an equidigital number, since it uses as much as digits as its factorization.

115230560053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6864227.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 115230560053 its reverse (350065032511), we get a palindrome (465295592564).

The spelling of 115230560053 in words is "one hundred fifteen billion, two hundred thirty million, five hundred sixty thousand, fifty-three".

Divisors: 1 7 2399 16793 6861821 48032747 16461508579 115230560053