115233304252241 has 4 divisors (see below), whose sum is σ = 131695204859712. Its totient is φ = 98771403644772.

The previous prime is 115233304252219. The next prime is 115233304252259. The reversal of 115233304252241 is 142252403332511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115233304252241 - 2²⁶ = 115233237143377 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115233304252195 and 115233304252204.

It is not an unprimeable number, because it can be changed into a prime (115233304252201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8230950303725 + ... + 8230950303738.

It is an arithmetic number, because the mean of its divisors is an integer number (32923801214928).

Almost surely, 2^{115233304252241} is an apocalyptic number.

It is an amenable number.

115233304252241 is a deficient number, since it is larger than the sum of its proper divisors (16461900607471).

115233304252241 is an equidigital number, since it uses as much as digits as its factorization.

115233304252241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16461900607470.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 115233304252241 its reverse (142252403332511), we get a palindrome (257485707584752).

The spelling of 115233304252241 in words is "one hundred fifteen trillion, two hundred thirty-three billion, three hundred four million, two hundred fifty-two thousand, two hundred forty-one".