Base | Representation |
---|---|
bin | 1010011110110000100010… |
… | …0001011101001100101101 |
3 | 1111210122021022222122112212 |
4 | 2213230020201131030231 |
5 | 3002300202300240440 |
6 | 40301501415540205 |
7 | 2266356032626532 |
oct | 247541041351455 |
9 | 44718238878485 |
10 | 11523540243245 |
11 | 374311905a598 |
12 | 136140a38a665 |
13 | 657885536534 |
14 | 2bba56d16d89 |
15 | 14eb48c64465 |
hex | a7b0885d32d |
11523540243245 has 4 divisors (see below), whose sum is σ = 13828248291900. Its totient is φ = 9218832194592.
The previous prime is 11523540243223. The next prime is 11523540243287. The reversal of 11523540243245 is 54234204532511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7557380366761 + 3966159876484 = 2749069^2 + 1991522^2 .
It is a cyclic number.
It is not a de Polignac number, because 11523540243245 - 230 = 11522466501421 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1152354024320 + ... + 1152354024329.
It is an arithmetic number, because the mean of its divisors is an integer number (3457062072975).
Almost surely, 211523540243245 is an apocalyptic number.
It is an amenable number.
11523540243245 is a deficient number, since it is larger than the sum of its proper divisors (2304708048655).
11523540243245 is an equidigital number, since it uses as much as digits as its factorization.
11523540243245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2304708048654.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 11523540243245 its reverse (54234204532511), we get a palindrome (65757744775756).
The spelling of 11523540243245 in words is "eleven trillion, five hundred twenty-three billion, five hundred forty million, two hundred forty-three thousand, two hundred forty-five".
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