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115243243425013 = 1185421312264691
BaseRepresentation
bin11010001101000000101000…
…100101100100110011110101
3120010001010221210002012012111
4122031000220211210303311
5110101121130304100023
61045034003135051021
733163023001341304
oct3215005045446365
9503033853065174
10115243243425013
11337a142658a130
1210b12ab5070a71
134c3c51169b432
142065b34a2643b
15d4cb1b9ba00d
hex68d028964cf5

115243243425013 has 8 divisors (see below), whose sum is σ = 125720059345056. Its totient is φ = 104766453742800.

The previous prime is 115243243424999. The next prime is 115243243425049. The reversal of 115243243425013 is 310524342342511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115243243425013 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115243243425053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3263998 + ... + 15528688.

It is an arithmetic number, because the mean of its divisors is an integer number (15715007418132).

Almost surely, 2115243243425013 is an apocalyptic number.

It is an amenable number.

115243243425013 is a deficient number, since it is larger than the sum of its proper divisors (10476815920043).

115243243425013 is a wasteful number, since it uses less digits than its factorization.

115243243425013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13118915.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 115243243425013 its reverse (310524342342511), we get a palindrome (425767585767524).

The spelling of 115243243425013 in words is "one hundred fifteen trillion, two hundred forty-three billion, two hundred forty-three million, four hundred twenty-five thousand, thirteen".

Divisors: 1 11 854213 9396343 12264691 134911601 10476658493183 115243243425013