115251353014433 has 4 divisors (see below), whose sum is σ = 117425906844948. Its totient is φ = 113076799183920.

The previous prime is 115251353014361. The next prime is 115251353014513. The reversal of 115251353014433 is 334410353152511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 70424203799569 + 44827149214864 = 8391913^2 + 6695308^2 .

It is a cyclic number.

It is not a de Polignac number, because 115251353014433 - 2¹⁰ = 115251353013409 is a prime.

It is a super-2 number, since 2×115251353014433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115251353010433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1087276915178 + ... + 1087276915283.

It is an arithmetic number, because the mean of its divisors is an integer number (29356476711237).

Almost surely, 2^{115251353014433} is an apocalyptic number.

It is an amenable number.

115251353014433 is a deficient number, since it is larger than the sum of its proper divisors (2174553830515).

115251353014433 is an equidigital number, since it uses as much as digits as its factorization.

115251353014433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2174553830514.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 115251353014433 in words is "one hundred fifteen trillion, two hundred fifty-one billion, three hundred fifty-three million, fourteen thousand, four hundred thirty-three".